-6a^2-22a-20=0

Solution for -6a^2-22a-20=0 equation:

-6a^2-22a-20=0

a = -6; b = -22; c = -20;
Δ = b2-4ac
Δ = -222-4·(-6)·(-20)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2}{2*-6}=\frac{20}{-12}
=-1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2}{2*-6}=\frac{24}{-12}
=-2
$